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Question

If the coefficient of x7 in the expression of (ax2+1bx)11 is equal to the coefficient of x7 in the expansion of (ax2bx2)11, then the relation between a and b is

A
ab=64
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B
ab=8
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C
ab=2
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D
None of these
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Solution

The correct option is A ab=64
(ax2+1bn)11
coefficient of x7
let nth term
(ax2)11n×(1bc)n
=x222nxn
=x233n
223n=7
227=3n
n=153=5
for (ax2bx2)11
mth term.
(ax)11m×(2bx2)m
11m2m=7
11+7=3m
m=6

1204600_1506290_ans_91b711523bf64396984c6e853ab7442b.jpg

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