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Question

If the coefficient of xn in (1+x)101(1−x+x2)100 is nonzero, then n cannot be of the form

A
3r+1
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B
3r
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C
3r+2
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D
none of these
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Solution

The correct option is C 3r+2
This can be re-written as
(1+x)[(1+x)(1x+x2)]100
=(1+x)(1+x3)100
=(1+x3)100+x(1+x3)100
Hence coefficient of xn will be
=100Cn3+100Cn13 ...(i)
Hence from i, we can say the n can of type , 3r or 3r+1 but not of type 3r+2.
Where rϵW

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