Index of (r+1)th Term from End When Counted from Beginning
If the coeffi...
Question
If the coefficient of xn in (1+x)101(1−x+x2)100 is nonzero, then n cannot be of the form
A
3r+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3r+2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C3r+2 This can be re-written as (1+x)[(1+x)(1−x+x2)]100 =(1+x)(1+x3)100 =(1+x3)100+x(1+x3)100 Hence coefficient of xn will be =100Cn3+100Cn−13 ...(i) Hence from i, we can say the n can of type , 3r or 3r+1 but not of type 3r+2. Where rϵW