Question

If the coefficients are rational numbers, then find the nature of the roots of the equation $2x^2-3x+2=0$

Answer 1

Here $a=2,b=-3,c=2$

$\Delta =b^2-4ac={(-3)}^2-4\times 2\times 2=9-16=-7<0$

$\therefore$ the roots are imaginary and conjugate to each other.