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Question

If the coefficients of 2nd, 3rd and 4th terms in the expansion of 1+xn, n N are in A.P., then n =
(a) 7
(b) 14
(c) 2
(d) none of these

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Solution

(a) 7
Coefficients of the 2nd, 3rd and 4th terms in the given expansion are:
C1n, C2n and C3nWe have:2×C2n=C1n+C3nDividing both sides by C2n, we get:2=C1nC2n+C3nC2n2=2n-1+n-236n-6=6+n2+2-3nn2-9n+14=0 n=7 n2 as 2>3 in the 4th term

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