If the coefficients of (2r+1)th term and (r+2)th terms in the expansion of (1+x)43 are equal, find r.
Given : (1+x)43
We know that the coefficient of the rth term in the expansion of (1+x)n is nCr−1
Therefore, the coefficient of the (2r+1)th and (r+2)th terms in the given expression are 43C2r+1−1 and 43C2r+1−1 and 43Cr+2−1 For these coefficient to be equal, we must have:
⇒2r=r+10 or 2r+r+1 =43
[∵nCr=nCs⇒r=s or r+s =n]
⇒r=14
[∵ for r =1 it gives the same term]