If the coefficients of (r+2)th and (2r+1)th terms (r≠1) are equal in the expansion of (1+x)43, then r=
A
12
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B
13
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C
14
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D
15
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Solution
The correct option is C14 Since coefficient of (r+2)th term is equal to coefficient of (2r+1)th term in the binomial expansion of (1+x)43 Therefore 43Cr+1=43C2r Now nCr=nCn−r ∴43−(r+1)=2r ⇒42=3r ⇒r=14