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Question

If the common difference of an A.P. is 3, then a20a15 is

A
5
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B
3
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C
15
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D
20
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Solution

The correct option is B 15
Given: d=3
We know:
an=a+(n1)d
a20a15=[a+19d][a+14d]
=5d
=5×3
=15
Hence, the answer is 15.

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