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Question

If the common difference of the A.P. in which T7=9 and T1,T2,T7 is least, is d then 20 d is-

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Solution

T1=a


T2=a+d


T7=a+6d=96d

T1T2T7=a(a+d)(a+6d)=N



N=(96d)(95d)9

N=(6d9)(5d9)9

dNdd=0

d=3320

then 20d=3320×20

=33

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