Question

Question 87

If the complement of an angle is ${62}^{\circ },$ then find its supplement.

Answer 1

Let the angle be$x^{\circ }$, we know sum of two complementary angles is ${90}^{\circ }$.
$\therefore x+{60}^{\circ }={90}^{\circ }\Rightarrow x={90}^{\circ }-{62}^{\circ }={28}^{\circ }$
Supplement of any angle is $({180}^{\circ }-angle)$.
$\therefore$ Supplement of x $={180}^{\circ }-{28}^{\circ }={152}^{\circ }$.