If the complement of an angle is 63- then the angle will be of -

Let the angle be x^∘ Given complement of x^∘ is 63^∘. ∴ (90 x)^∘ = 63^∘ ⇒ x^∘ = 90^∘ 63^∘ = 27^∘ Therefore the required angle is 27^∘ nbsp; nbsp;. nbs ...

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Standard IX

Mathematics

Angles and Types of Angles

If the comple...

Question

If the complement of an angle is $63^{\circ}$ then the angle will be of __.

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Solution

Let the angle be $x^{\circ}$
Given complement of $x^{\circ}$ is $63^{\circ}$ .

$∴ (90 - x)^{\circ} = 63^{\circ} \Rightarrow x^{\circ} = 90^{\circ} - 63^{\circ} = 27^{\circ}$
Therefore the required angle is $27^{\circ}$ .

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If the complement of an angle is 63∘ then the angle will be of __.

Let the angle be x∘ Given complement of x∘ is 63∘. ∴(90−x)∘=63∘⇒x∘=90∘−63∘=27∘ Therefore the required angle is 27∘.

If the complement of an angle is $63^{\circ}$ then the angle will be of __.

Let the angle be $x^{\circ}$
Given complement of $x^{\circ}$ is $63^{\circ}$ .

$∴ (90 - x)^{\circ} = 63^{\circ} \Rightarrow x^{\circ} = 90^{\circ} - 63^{\circ} = 27^{\circ}$
Therefore the required angle is $27^{\circ}$ .