If the complement of an angle is 79- then the angle will be of

Let the angle be x^∘ Given complement of x^∘ is 79^∘ ∴ (90 x)^∘ = 79^∘ ⇒ x^∘ = 90^∘ 79^∘ = 11^∘ Therefore the required angle is 11^∘ nbsp; nbsp;. nbsp ...

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Standard VI

Mathematics

Complementary Angles

If the comple...

Question

If the complement of an angle is $79^{\circ}$ then the angle will be of

1^{\circ}

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101^{\circ}

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79^{\circ}

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11^{\circ}

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Solution

The correct option is D $11^{\circ}$
Let the angle be $x^{\circ}$
Given complement of $x^{\circ}$ is $79^{\circ}$

$∴ (90 - x)^{\circ} = 79^{\circ} \Rightarrow x^{\circ} = 90^{\circ} - 79^{\circ} = 11^{\circ}$
Therefore the required angle is $11^{\circ}$ .

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Similar questions

Q. If the complement of an angle is

79^{\circ}

then the angle will be of

Question 4
If the complement of an angle is $79^{\circ}$ then the angle will be of
(a) $1^{\circ}$
(b) $11^{\circ}$
(c) $79^{\circ}$
(d) $101^{\circ}$

If 30% of an angle is the complement of $15^{\circ}$ , then the angle is ______ .

Q. An angle is

\frac{2}{3}

of its complement, then the angle is _______ and its complement angle is _______

If the supplement of an angle is three times its complement, then angle is:

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If the complement of an angle is 79∘ then the angle will be of

The correct option is D 11∘Let the angle be x∘ Given complement of x∘ is 79∘ ∴(90−x)∘=79∘⇒x∘=90∘−79∘=11∘ Therefore the required angle is 11∘.

If the complement of an angle is $79^{\circ}$ then the angle will be of

The correct option is D $11^{\circ}$
Let the angle be $x^{\circ}$
Given complement of $x^{\circ}$ is $79^{\circ}$

$∴ (90 - x)^{\circ} = 79^{\circ} \Rightarrow x^{\circ} = 90^{\circ} - 79^{\circ} = 11^{\circ}$
Therefore the required angle is $11^{\circ}$ .