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Question

If the complex number z=x+iy satisfies the condition |z+1|=1 , then z lies on

A
Circle with centre (1,0) and radius 1
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B
yaxis
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C

none of these

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D
xaxis
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Solution

The correct option is A Circle with centre (1,0) and radius 1

|z+1|=1

|x+iy+1|=1

|x+1+iy|=1

(x+1)2+y2=1

(x+1)2+y2=12

(squaring both sides)

Clearly, above equation represents the equation of a circle.

Centre (1,0) and radius =1

Hence, option (B) is correct.


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