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Question

If the concentration of a sodium hydroxide aqueous solution is 50% by mass, calculate the molality of the solution.

A
25.0 m
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B
0.5 m
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C
12.5 m
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D
13.8 m
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Solution

The correct option is A 25.0 m
Let's assume mass of the solution be 100 g
50% (w/w) means 50 g of NaOH is present in 100 g of the solution.
Mass of the solvent in the solution
= 100 - mass of solute
Mass of the solvent = 50 g
Number of moles of NaOH
= given massmolar mass=5040 mol

Molality = moles of solutemass of solvent in g×1000

Molality = 50/4050×1000

Molality = 25 m

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