Question

If the concentration of glucose $\left(C_6{H}_{12}{O}_6\right)$ in blood is $0.9g{L}^{-1},$ what will be the molarity of glucose in blood ?

(a) 5 M (b) 50 M (c) 0.005 M (d) 0.5 M

Answer 1

(c)

In the given question, $0.9g{L}^{-1}$ means that 1000 mL (or 1L) solution contains 0.9 g of glucose.

$\therefore$ Number of moles $=0.9gglucose=\frac{0.9}{180}$mol glucose

$=5\times {10}^{-3}$ mol glucose

(where, molecular mass of glucose $\left(C_6{H}_{12}{O}_6\right)=12\times 6+12\times 1+6\times 16=180u$

i.e., 1L solution contains 0.05 mole glucose or the molarity of glucose is 0.005 M.