If the concentration of OH− ions in the reaction: Fe(OH)3(s)⇌Fe3+(aq)+3OH−(aq.) is decreased by 1/4 times, then equilibrium concentration of Fe3+ will increase by:
A
64 times
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B
4 times
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C
8 times
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D
16 times
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Solution
The correct option is A64 times If the concentration of OH− ions in the reaction: Fe(OH)3(s)⇌Fe3+(aq)+3OH−(aq.) is decreased by 1/4 times, then equilibrium concentration of Fe3+ will increase by 64 times. K=[Fe3+]i[OH−]3i....(1) K=[Fe3+]f[OH−]3f....(2) [Fe3+]i and [OH−]3i are the inital concentrations. [Fe3+]f and [OH−]3f are the final concentrations. From (1) and (2)
[Fe3+]i[OH−]3i=[Fe3+]f[OH−]3f.....(3) The concentration of OH− ions is decreased by 1/4 times [OH−]f=[OH−]i4....(4) Substitute equation (4) in equation (3) [Fe3+]i[OH−]3i=[Fe3+]f([OH−]i4)3 [Fe3+]i=[Fe3+]f(14)3 43×[Fe3+]i=[Fe3+]f 64×[Fe3+]i=[Fe3+]f