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Standard XII

Chemistry

Dalton's Law of Partial Pressures

If the concen...

Question

If the concentration of water vapour in the air is $1 %$ and the total atmospheric pressure equals $1$ atm then the partial pressure of water vapour is?

0.1

atm

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1

mm Hg

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7.6

mm Hg

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100

atm

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Solution

The correct option is C $7.6$ mm Hg
According to Dalton's law of partial pressures,
pressure $\propto Λ_{water vapour}$
Pressure of water vapour= $(\frac{1}{100}) 1$ atm=0.01 atm
1 atm $⟹$ 760 mm of Hg
0.01 atm $⟹$ 7.6 mm of Hg

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Q. For a solution if

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p_{B}^{0} = 840 m m H g

under atmospheric conditions and vapour pressure of solution is 1 atm then find
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ii) Composition of vapour in equilibrium with solution.

Q. At

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and that of pure liquid

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. If a solution of

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Q. At

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the vapour pressure of pure liquid A is 250 mm of Hg and that of pure liquid B is 1000 mm of Hg. If a solution of A and B boils at

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and 1 atm pressure, the amount of A in the mixture is (1 atm = 760 mm Hg)

Q. At

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If the concentration of water vapour in the air is 1% and the total atmospheric pressure equals 1atm then the partial pressure of water vapour is?

The correct option is C 7.6 mm HgAccording to Dalton's law of partial pressures,pressure ∝Λwater vapourPressure of water vapour=(1100)1 atm=0.01 atm1 atm⟹ 760 mm of Hg0.01 atm⟹ 7.6 mm of Hg

If the concentration of water vapour in the air is $1 %$ and the total atmospheric pressure equals $1$ atm then the partial pressure of water vapour is?

The correct option is C $7.6$ mm Hg
According to Dalton's law of partial pressures,
pressure $\propto Λ_{water vapour}$
Pressure of water vapour= $(\frac{1}{100}) 1$ atm=0.01 atm
1 atm $⟹$ 760 mm of Hg
0.01 atm $⟹$ 7.6 mm of Hg