If the conditional p→q has truth value 'F' then which of the following proportions has truth value 'F'?
A
−p→q
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B
q→p
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C
∼p→∼q
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D
p↔q
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Solution
The correct option is C∼p→∼q p→qcanbewrittenas:¯¯¯pq+p¯¯¯q=FLet′ssee¯¯¯p→¯¯¯qcanbewrittenas¯¯¯¯¯¯p¯¯¯q+¯¯¯p¯¯¯¯¯¯q=p¯¯¯qׯ¯¯pq+FHence,Chasthesquaretruthvalue′F′