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Question

If the conjugate of (x + iy) (1 - 2i) be 1 + i , then

A
x=3/5
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B
x=1/3
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C
x + iy = 1i12i
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D
x - iy = 1i1+2i
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Solution

The correct option is A x=3/5
(x+iy)(12i)
=x2ix+iy2i2y
x2ix+iy+2y
=x+2y+i(y2x)
Conjugate =x+2yi(y2x)1+i
Comparing the values
2xy=1
x+2y=1
on solving we get x=35,y=15

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