If the coordinates of a point be given by the equation x=a(1−cosθ),y=asinθ, then the locus of the point will be
A circle
On eliminating \theta, we get the required locus.
Since x=a(1−cosθ)⇒x−a=−acosθ .................(i)
and y=asinθ ................(ii)
Now adding the squares of (i) and (ii), we get
x2+y2−2ax=0, which is equation of a circle.