1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# If the coordinates of the extermities of diagonal of a square are (2,âˆ’1) and (6,2), then the coordinates of extremities of other diagonal are

A
(52,52)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
(112,32)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
(112,32)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(52,52)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C (112,−32)Coordinationofmid−point0=(6+22,2−12)=(4,12)AB=BC⇒(x1−2)2+(y1+1)2=(x1−6)2+(y1−2)2⇒8x1+6y1=35→(i)AO=BO⇒(2−4)2+(−1−12)2=(x1−4)2+(y1−12)2⇒4+94=x21+y21−8x1−y1+16+14⇒x21+y21−8x1−y1=−10→(ii)fromequation(i)putx1=35−6y18inequation(ii)⇒(35−6y18)2+y21−(35−6y1)y1=−10⇒4y21−4y1−15=0⇒(2y1+3)(y1−5)=0⇒y1=−32,5y1=−32→x1=35−6×−328=112y1=5→x1=35−6×58=58Theverticesofothertwoverticesare(112,−32)and(58,5)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Integrating Solids into the Picture
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program