If the coordinates of two points A and B are (3,4) and (5,-2) respectively. Then, the coordinates of any point P, if PA = PB and area of Δ PAB = 10, are
(7, 2), (1, 0)
Let the coordinates of P be(x,y). Then,PA=PB⇒PA2=PB2⇒(x−3)2+(y−4)2=(x−5)2+(y+2)2⇒x−3y−1=0 ⋯⋯⋯(i)Now,Area of ΔPAB=10⇒12∣∣ ∣∣xy13415−21∣∣ ∣∣=±10⇒6x+2y−26=±20⇒6x+2y−46=0 or 6x+2y−6=0⇒3x+y−23=0 or 3x+y−23=0Solving x−3y−1=0 and 3x+y−23=0We get x=7,y=2Solving x−3y−1=0 and 3x+y=30We get x=1,y=0Thus,the cordinates of P are (7,2) or (1,0).Hence,(b) is the correct answer.