If the critical angle for the medium of a prism is C and the angle of prism is A, then there will be no emergent ray when
The light entering the prism at surface AB, will not be able to come out from the surface AC, if total internal reflection (TIR) takes place at this surface.
As TIR takes place at surface AC
(r2)min>C
Since r1+r2=A
⇒r2=A−r1
⇒(r2)min=A−(r1)max …(1)
But (r1)max is possible when incident angle is maximum ⇒imax=90∘
i.e., incident ray grazes the interface AB.
Now, applying Snell's Law at AB,
1×sin i=μsin r1
⇒sin(90∘)=μsinr1
⇒r1=sin(−1)(1μ)
⇒r1=C …(2)
From equations (1) and (2), we get
r1+r2>2C …(3)
Since, r1+r2=A
Therefore, the condition becomes
A>2C