If the critical angle for total internal reflection from a medium to vacuum is $30^{0}$ , the velocity of light in the medium is

3×10⁸ m/sec

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1.5×10⁸ m/sec

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6×10⁸ m/sec

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√3×10⁸ m/sec

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Solution

The correct option is B
1.5×10⁸ m/sec

$We have, n s i n 30^{0} = 1 s i n 90^{0} \Rightarrow n = 2 Also V = \frac{c}{n} = \frac{3 \times 10^{8}}{2} = 1.5 \times 10^{8} m s^{- 1}$

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Fill in the blanks to complete the following sentences :

(a) Total internal reflection occurs only when a ray of light passes from a .............................medium to a ..........................medium.

(b) Critical angle is the angle of ................in denser medium for which the angle of ..............in rarer medium is .................

Q. Which of the following conditions are necessary for total internal reflection to take place at the boundary of two optical media ?
1. Light is passing from optically denser medium to optically rarer medium.
2. Light is passing from optically rarer medium to optically denser medium.
3.Angle of incidence is greater than the critical angle.
4.Angle of incidence is less than the critical angle.

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If the critical angle for total internal reflection from a medium to vacuum is 300 , the velocity of light in the medium is

The correct option is B 1.5×108 m/sec We have, n sin300=1 sin 900⇒n=2Also V=cn=3×1082=1.5×108 ms−1

If the critical angle for total internal reflection from a medium to vacuum is $30^{0}$ , the velocity of light in the medium is

The correct option is B
1.5×10⁸ m/sec

$We have, n s i n 30^{0} = 1 s i n 90^{0} \Rightarrow n = 2 Also V = \frac{c}{n} = \frac{3 \times 10^{8}}{2} = 1.5 \times 10^{8} m s^{- 1}$