Question

If the critical angle of a medium is 30${}^{\circ }$, the polarizing angle for the medium is about

• A. $ta{n}^{-1}\left(\sqrt{2}\right)$
• B. $ta{n}^{-1}\left(2\right)$
• C. $ta{n}^{-1}\left(\frac{1}{2}\right)$
• D. $si{n}^{-1}\left(\frac{1}{2}\right)$

Answer 1

The correct option is B $ta{n}^{-1}\left(2\right)$

tan (polarizing angle) $=\frac{1}{sin\left(criticalangle\right)}$
So, $tan\left(p\right)=\frac{1}{sin{30}^{\circ }}$

$=\frac{1}{1/2}(\because sin{30}^{\circ }=\frac{1}{2})$
$tan\left(p\right)=2$
So, $p=ta{n}^{-1}\left(2\right)$