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Question

If the critical point as well as stationary point of the function f(x)=exx is x=a, then value of a is:

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Solution

f(x)=exx
The above function is not defined at x=0.
Differentiating the function and equating it to zero.
(exxex)x2=0
ex(x1)x2=0
ex is positive for all x.
Therefore x=1 is critical point

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