If the critical point as well as stationary point of the function f(x)=exx is x=a, then value of a is:
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Solution
f(x)=exx The above function is not defined at x=0. Differentiating the function and equating it to zero. (exx−ex)x2=0 ex(x−1)x2=0 ex is positive for all x. Therefore x=1 is critical point