If the cube given below is turned twice in the right hand direction (clockwise)( $\to$ ), then the hidden numbers will be :

1, 2, 5

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2,3, 5

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4, 6, 5

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4, 3, 1

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Solution

The correct option is A 2,3, 5
$1$ will always be visible irrespective of how many times you turned to right.
$6$ and $4$ will be at the top face and right side face respectively after turned twice and hence they will also be visible.
Remaining $2, 3, 5$ will not be visible

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