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Question

If the cube root of unity are 1,ω,ω2, then the roots of the equation (x+1)3+8=0 are

A
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B
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C
-1, -1, -1
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D
None of the above
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Solution

The correct option is B
(x+1)3+8=0x+1=2,2ω,2ω2x=12,12ω,12ω2=3,12ω,12ω2

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