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Question

If the cube roots of unity be 1,w,w,w2 ,then the roots of the equation (x1)3+8=0 are

A
-1, 1+2ω,1+2ω2
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B
-1, 1-2ω,1-2ω2
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C
-1,-1,-1
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D
None of these
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Solution

The correct option is B -1, 1-2ω,1-2ω2

CONVENTIONAL APPROACH:
(x1)3=8 x1=(8)13
x1=2,2w,2w2 x=1,12w,12w2
Trick:By inspection, we see that (b) satisfies the equation i.e,
(11)3+80,(12w1)3+80(12w21)2+80.



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