Question

If the current in an electric bulb increases by $2$%, what will be the change in the power of a bulb? (Assume that the resistance of the filament of a bulb remains constant)

• A. decreases by $2$%
• B. increases by $2$%
• C. decreases by $4$%
• D. increases by $4$%

Answer 1

The correct option is D increases by $4$%

$P=I^{2}R\%I=2\%\%P=2\left(\%I\right)+\%R\%P=2\times 2+0=4\%$

There will be $4\%$ increase in the power of the bulb.