If the current in the toroidal solenoid increases uniformly from zero to 6.0A in 3.0μs. Self inductance of the toroidal solenoid is 40μH. The magnitude of self induced emf is :
A
80V
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B
160V
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C
24V
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D
48V
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Solution
The correct option is A80V Current in toroidal solenoid increases uniformly from 0 to 6.0A in 3.0μs. Magnitude of self induced emf is given by |ϵ|=L∣∣∣didt∣∣∣ [Symbols have usual meanings] =(40×10−6)(6−03.0×10−6)=80V