If the current population of Chennai city is $3888180$ and the average rate of population growth in Bangalore city is $10 %$ p.a., what can city planners expect the population of Chennai city to be in $10$ years?

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Solution

Given, $P = 3888180, r = 10 %, n = 10$
We know, $A = P [{(1 + \frac{r}{100})}^{n}]$
$\Rightarrow A = 3888180 [{(1 + \frac{10}{100})}^{10}]$
$\Rightarrow A = 10084772$
Hence, the population of Chennai city in $10$ years is $10084772$ .

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If the current population of Chennai city is 3888180 and the average rate of population growth in Bangalore city is 10% p.a., what can city planners expect the population of Chennai city to be in 10 years?

Given, P=3888180,r=10%,n=10We know, A=P[(1+r100)n]⇒A=3888180[(1+10100)10]⇒A=10084772Hence, the population of Chennai city in 10 years is 10084772.

If the current population of Chennai city is $3888180$ and the average rate of population growth in Bangalore city is $10 %$ p.a., what can city planners expect the population of Chennai city to be in $10$ years?

Given, $P = 3888180, r = 10 %, n = 10$
We know, $A = P [{(1 + \frac{r}{100})}^{n}]$
$\Rightarrow A = 3888180 [{(1 + \frac{10}{100})}^{10}]$
$\Rightarrow A = 10084772$
Hence, the population of Chennai city in $10$ years is $10084772$ .