The correct option is C unchanged
Current sensitivity of galvanometer is deflection per unit current i.e
ϕI = NABk..................(i)
Similarly voltage sensitivity is deflection per unit voltage
i.e. ϕV = NABkIV= NABk1R..................(i)
From (i) and (ii)
Voltage sensitivity = current sensitivity X 1resistance
Now if current sensitivity is doubled, then the resistance in the circuit will also be doubled since it is proportional to the length of the wire, then voltage sensitivity
= (2 x current sensitivity) X 12×resistance
= (current sensitivity) X 1resistance
Hence, voltage sensitivity will remain unchanged.