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Byju's Answer
Standard XII
Mathematics
Directrix
If the curve ...
Question
If the curve
2
x
2
+
x
y
−
y
2
−
3
x
+
4
y
+
k
=
0
passes through the origin, then the value of
k
is _____
A
1
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B
−
1
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C
0
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D
2
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Solution
The correct option is
D
0
If the curve
2
x
2
+
x
y
−
y
2
−
3
x
+
4
y
+
k
=
0
passes through origin, this means that it passes through
(
0
,
0
)
Substitute
x
=
0
and
y
=
0
in
2
x
2
+
x
y
−
y
2
−
3
x
+
4
y
+
k
=
0
to find the value of
k
as follows:
2
(
0
)
2
+
(
0
)
(
0
)
−
(
0
)
2
−
3
(
0
)
+
4
(
0
)
+
k
=
0
that is
k
=
0
.
Suggest Corrections
0
Similar questions
Q.
If
y
=
2
x
+
K
is a diameter to the circle
2
(
x
2
+
y
2
)
+
3
x
+
4
y
−
1
=
0
, then
K
equals
Q.
The curve passing through the point (1, 1) satisfies the differential equation
d
y
d
x
+
√
(
x
2
−
1
)
(
y
2
−
1
)
x
y
=
0
If the curve passes through the point
(
√
2
,
k
)
then the value of [k] is (where [.] represents greatest integer function)
Q.
The curve passing through the point
(
1
,
1
)
satisfies the differential equation
d
y
d
x
+
√
(
x
2
−
1
)
(
y
2
−
1
)
x
y
=
0
. If the curve passes through the point
(
√
2
,
k
)
, then the largest value of
|
[
k
]
|
is
(where,
[
.
]
represents the greatest integer function)
Q.
Let
y
=
y
(
x
)
be a curve passing through the point
(
1
,
1
)
and satisfying
d
y
d
x
+
√
(
x
2
−
1
)
(
y
2
−
1
)
x
y
=
0.
If the curve passes through the point
(
√
2
,
k
)
,
then the largest value of
|
[
k
]
|
is
(Here,
[
.
]
represents the greatest integer function)
Q.
If a curve satisfying
x
y
1
−
4
y
−
x
2
√
y
=
0
passes through
(
1
,
(
log
4
)
2
)
, then the value of
y
(
2
)
(
log
32
)
2
is equal to
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