Question

If the curve $2x^2+xy-y^2-3x+4y+k=0$ passes through the origin, then the value of $k$ is _____

• A. $1$
• B. $-1$
• C. $0$
• D. $2$

Answer 1

Answer: (C)

$0$

If the curve $2x^2+xy-y^2-3x+4y+k=0$ passes through origin, this means that it passes through $(0,0)$

Substitute $x=0$ and $y=0$ in $2x^2+xy-y^2-3x+4y+k=0$ to find the value of $k$ as follows:

$2(0{)}^2+(0\left)\right(0)-(0{)}^2-3\left(0\right)+4\left(0\right)+k=0$ that is $k=0$.