If the curved surface area of a solid right circular cylinder of height h and radius r is one-third of its total surface area, then
A
h=13r
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B
h=12r
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C
h=r
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D
h=2r
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Solution
The correct option is Bh=12r We know, curved surface area of a cylinder of radius "R" and height "h" =2πRh Total surface area of a cylinder of radius "r" and height "h" =2πr(r+h) Given, 2πRh=13×2πr(r+h) ∴h=13×(r+h) ∴23h=13r ∴h=12r