If the curves x2a2-y2b2-1 and x225-y216-1 cut each other orthogonally- then a2-b2-

The correct option is A 9 There are two curves x^2a^2+ y^2b^2=1 and x^225+y^216=1 If two curves intersect each other orthogonally, then a^2 ...

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Angle of Intersection of Two Curves

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Question

If the curves $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ and $\frac{x^{2}}{25} + \frac{y^{2}}{16} = 1$ cut each other orthogonally, then $a^{2} - b^{2} =$

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\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{p^{2}} - \frac{y^{2}}{m^{2}} = 1

If the curves $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ and $\frac{x^{2}}{l^{2}} - \frac{y^{2}}{m^{2}} = 1$ cut each other orthogonally, then

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{α^{2}} - \frac{y^{2}}{β^{2}} = 1

If the curves $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ and $\frac{x^{2}}{α^{2}} + \frac{y^{2}}{β^{2}} = 1$ cut each other orthogonally,

\frac{x^{2}}{25} + \frac{y^{2}}{16} = 1

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{4} = 1

a^{2}

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