If the deBroglie wavelenght of an electron is equal to 103 times the wavelength of a photon of frequency 6 - 1014 Hz- then the speed of electron is equal to - Speed of light - 3 - 108 m-s Planck-s constant - 6-63 - 1034 J - Mass of electron - 9-1 1031 kg

The correct option is D 1.45× 10^6m/s hmv=10^ 3(3× 10^86× 10^14) v=6.63× 10^ 34× 6× 10^149.1× 10^ 31× 3× 10^5 ...

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Standard XII

Physics

Matter Waves

If the deBrog...

Question

If the deBroglie wavelenght of an electron is equal to $10^{3}$ times the wavelength of a photon of frequency $6 \times 10^{14} H z$ , then the speed of electron is equal to : (Speed of light = $3 \times 10^{8} m / s$ Planck's constant = $6.63 \times 10^{34} J$ . Mass of electron = $9.1 10^{31} k g$ )

1.45 \times 10^{6} m / s

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1.75 \times 10^{6} m / s

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1.8 \times 10^{6} m / s

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1.1 \times 10^{6} m / s

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Solution

The correct option is D $1.45 \times 10^{6} m / s$
$\frac{h}{m v} = 10^{- 3} (\frac{3 \times 10^{8}}{6 \times 10^{14}})$
$v = \frac{6.63 \times 10^{- 34} \times 6 \times 10^{14}}{9.1 \times 10^{- 31} \times 3 \times 10^{5}}$

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If the deBroglie wavelenght of an electron is equal to 103 times the wavelength of a photon of frequency 6×1014Hz, then the speed of electron is equal to : (Speed of light = 3×108m/s Planck's constant = 6.63×1034J . Mass of electron = 9.11031kg)

The correct option is D 1.45×106m/shmv=10−3(3×1086×1014)v=6.63×10−34×6×10149.1×10−31×3×105

The correct option is D $1.45 \times 10^{6} m / s$
$\frac{h}{m v} = 10^{- 3} (\frac{3 \times 10^{8}}{6 \times 10^{14}})$
$v = \frac{6.63 \times 10^{- 34} \times 6 \times 10^{14}}{9.1 \times 10^{- 31} \times 3 \times 10^{5}}$