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Question

If the deBroglie wavelength of an electron is equal to 103 times the wavelength of a photon of frequency 6×1014 Hz, then the speed of an electron is equal to:
(Speed of light, c=3×108 ms1Planck's constant, h=6.63×1034 JsMass of electron, me=9.1×1031 kg)

A
1.1×106 ms1
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B
1.7×106 ms1
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C
1.8×106 ms1
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D
1.45×106 ms1
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Solution

The correct option is D 1.45×106 ms1
Given that, the de-Broglie wavelength,
λ=103(3×1086×1014) [λp=cν]

The deBroglie wavelength is given by,

λ=hmv

v=6.63×1034×6×10149.1×1031×3×105

v=1.45×106 ms1

Hence, option (D) is correct.

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