If the degree of freedom of a gas are f, then the ratio of two specific heats $\frac{C_{p}}{C_{v}}$ is given by

$\frac{2}{f} + 1$

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$1 - \frac{2}{f}$

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$1 + \frac{1}{f}$

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$1 - \frac{1}{f}$

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Solution

The correct option is A
$\frac{2}{f} + 1$

$\frac{2}{f} + 1$

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Similar questions

If the degree of freedom of a gas are f, then the ratio of two specific heats $\frac{C_{p}}{C_{v}}$ is given by

\frac{C_{P}}{C_{V}}

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(\frac{C_{P}}{C_{V}})

\frac{C_{P}}{C_{V}}

^{'} f^{'}

(\frac{C_{P}}{C_{V}})

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