Question

If the degree of ionization $\left(\alpha \right)$ of a weak electrolyte $AB$ is very less, then $\alpha$ is

• A. directly proportional to the square root of volume of solution
• B. inversely proportional to the dilution
• C. inversely proportional to the square root of concentration
• D. directly proportional to concentration

Answer 1

Answer: (A), (C)

directly proportional to the square root of volume of solution
inversely proportional to the square root of concentration

For weak electrolyte AB:
$AB\to A^{+}+B^{-}$
C - -
C(1-$\alpha$) C$\alpha$ C$\alpha$
$K=\frac{C\alpha \times C\alpha }{C(1-\alpha )}=C{\alpha }^{2}if\alpha \ll 1$
$\alpha =\sqrt{\frac{K}{C}}⟹$ it is directly proportional to $\sqrt{KV}$