If the degree of polynomial $p (y)$ is $a$ , then the maximum number of zeroes of $p (y$ ) would be:

a + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a - 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $a$
We know, the number of zeroes of a polynomial is equal to or less than the degree of the polynomial.
Hence, if the degree of the polynomial is $a$ , then the number of zeros it can have is $a, a - 1, a - 2, . . . . . . .0$ , i.e. it can have $a$ number of zeros.
Hence, the maximum number of zeroes is $a$ .

Therefore, option $C$ is correct.

Suggest Corrections

Similar questions

If‘-p’ and ‘q’ are the zeroes of the polynomial
$x^{2} - b x + c$ , then the zeroes of the polynomial $x^{2} - b x y + c y^{2}$ are ________.

‘- p’ and ‘q’ are the zeroes of the polynomial $x^{2} - b x + c$ . The zeroes of the polynomial $x^{2} - b x y + c y^{2}$ are:

p (y) = 5 y^{3} - 2 y^{2} + y + 10

y

‘-p’ and ‘q’ are the zeroes of the polynomial
$x^{2} - b x + c$ .
The zeroes of the polynomial $x^{2} - b x y + c y^{2}$ are

p (y) = y + 1

Join BYJU'S Learning Program