Question

If the density of a gas at sea level at $0^{o}C$ is $1.29kg{m}^{-3}$, what is its molar mass. (Pressure $=1$ bar).

Answer 1

$d=\frac{PM}{RT}$

$⟹M=\frac{dRT}{P}$

$=\frac{1.29\times {10}^{-3}kgd{m}^{-3}\times 0.083\times 273}{1}$

$=29.23\times {10}^{-3}kgmo{l}^{-1}$

$=29.23gmo{l}^{-1}$