The correct option is D Rhombus
Given, in quadrilateral ABCD
AB || CD
and, BC || DA
So, it is a parallelogram.
We know that opposite angles of a parallelogram are equal.
∴ ∠DAB = ∠BCD
Also, the diagonal AC bisects the angles ∠DAB and ∠BCD
∴ ∠DAC=∠CAB =∠BCA=∠ACD
Therefore, the two triangles △ABC and △CDA are isoceles triangle.
Hence, AB = BC and CD = DA
Also, △ABS≅△CDA by ASA criteria
∠CAB=∠DAC
side AC (common side)
∠BCA=∠ACD
Therefore,
sides AB = BC = CD = DA (corresponding parts)
The given quadrilateral is a rhombus (by definition)