Let l and b be the length and breadth of the rectangle, where diagonal = 17 cm and perimeter = 46 cm.
So, as per the question
Perimeter = 2 (l + b)
46 = 2 (l + b)
l + b = 23 ..... (i)
Now, in the triangle formed by the adjacent sides and one diagonal of the rectangle, using Pythagoras theorem, we have
l2 + b2 = (diagonal)2
l2 + b2 = 172
l2 + (23 − l)2 = 172 [From (i)]
l2 +l2 + 232 − 46l = 289
2l2 + 529 − 46l = 289
2l2 − 46l + 240 = 0
l2 − 23l + 120 = 0
l2 − 15l − 8l + 120 = 0
l(l − 15) − 8(l − 15) = 0
(l − 15) (l − 8) = 0
l = 15 cm or l = 8 cm
If l = 15 cm, then from (i), b = 23 − 15 = 8 cm.
If l = 8 cm, then from (i), b = 23 − 8 = 23 cm.
Therefore
Area of the rectangle = l b = 15 8 = 120 cm2
Hence, the correct option is (c).