If the diagonals $A C$ and $B D$ of a quadrilateral $A B C D$ bisect each other, then $A B C D$ is :

Parallelogram

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Rectangle

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Rhombus

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None of these

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Solution

The correct option is A Parallelogram

Parallelogram .
The diagonals (lines linking opposite corners) of parallelogram bisect each other. Each diagonal cuts the other into two equal parts.

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Similar questions

A B C D

(1) $A B C D$ is a Rhombus	(a) $¯ ¯¯¯¯¯¯ ¯ A C$ and $¯ ¯¯¯¯¯¯¯ ¯ B D$ bisect each other.
(2) $A B C D$ is a Parallelogram	(b) $¯ ¯¯¯¯¯¯ ¯ A C$ and $¯ ¯¯¯¯¯¯¯ ¯ B D$ bisect each other at an right angle.
(3) $A B C D$ is Rectangle	(c) $¯ ¯¯¯¯¯¯ ¯ A C$ and $¯ ¯¯¯¯¯¯¯ ¯ B D$ are congruent and bisect each other at an right angle.
(4) $A B C D$ is Square	(d) $¯ ¯¯¯¯¯¯ ¯ A C$ and $¯ ¯¯¯¯¯¯¯ ¯ B D$ are congruent and bisect each other.

A B C D

∠ A = 45^{\circ},

∠ B

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