The correct option is C Parallelogram
From the given figure, consider the triangles AOB and COD.
AO = OC (Given)
BO = OD (Given)
∠AOB=∠COD ( vertically opposite angles)△AOB≅△COD
By corresponding parts of congruent triangles,
∠ABO=∠CDO-------(i)
But, (i) forms alternate interior angles. Hence, AB || CD.
Similarly, AD || BC.
Since, both the pair of opposite sides are parallel, quadrilateral ABCD is a parallelogram.