If the diagonals of a rhombus are 24 dm and 10 dm then the perimeter of rhombus will be

68 dm

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60 dm

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52 dm

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50 dm

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Solution

The correct option is C 52 dm
In rhombus diagonals are 24 dm and 10 dm
We know formula of perimeter= $2 \sqrt{(d i g o n a l)^{2} + (d i g o n a l)^{2}}$
Then perimeter of rhombus = $2 \sqrt{(24)^{2} + (10)^{2}} = 2 \sqrt{576 + 100} = 2 \times 26 = 52$ dm

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