If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ___ its original area.

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Solution

The correct option is C 4 times
We know that,
Area of a rhombus $= \frac{1}{2} \times d_{1} \times d_{2}$
where, $d_{1}$ and $d_{2}$ are diagonals of the rhombus.
If diagonals get doubled, then the area $= \frac{1}{2} [(2 d_{1}) \times (2 d_{2})] = 4 (\frac{1}{2} \times d_{1} \times d_{2})$
Hence, the new area becomes 4 times its original area.

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If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ___ its original area.

The correct option is C 4 times We know that, Area of a rhombus =12×d1×d2 where, d1 and d2 are diagonals of the rhombus. If diagonals get doubled, then the area =12[(2d1)×(2d2)]=4(12×d1×d2) Hence, the new area becomes 4 times its original area.