If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

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Solution

1 m = 100 cm

1 cm = 10^–2 m

Length of the scale = 20 cm

= 20 × 10^–2 m

Diameter of a carbon atom = 0.15 nm

= 0.15 × 10^–9 m

One carbon atom occupies 0.15 × 10^–9 m.

∴ Number of carbon atoms that can be placed in a straight line

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If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

1 m = 100 cm 1 cm = 10–2 m Length of the scale = 20 cm = 20 × 10–2 m Diameter of a carbon atom = 0.15 nm = 0.15 × 10–9 m One carbon atom occupies 0.15 × 10–9 m. ∴ Number of carbon atoms that can be placed in a straight line

1 m = 100 cm

1 cm = 10^–2 m

Length of the scale = 20 cm

= 20 × 10^–2 m

Diameter of a carbon atom = 0.15 nm

= 0.15 × 10^–9 m

One carbon atom occupies 0.15 × 10^–9 m.

∴ Number of carbon atoms that can be placed in a straight line