If the diameter of a semicircular protractor is $14 c m$ then find its perimeter.

36 c m

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76 c m

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112 c m

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162 c m

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Solution

The correct option is B $36 c m$
Diameter $= 14 c m$
Radius= $\frac{D i a m e t e r}{2} = \frac{14 c m}{2} = 7 c m$
Length of the semicircular part $= π r = \frac{22}{7} \times (7) = 22 c m$
Total perimeter=length of semicircular part +Diameter
$= 22 c m + 14 c m = 36 c m$
Thus, the perimeter of the protractor is $36 c m$

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